Question

The average value of the numbers n n for n = 2, 4, 6 ... 180

Answer 1

Given :-

AP :- 2, 4, 6, … 180

Here,

First term = a = 2

Common difference = d = 4 - 2 = 2

Last term = An = 180

We know that,

An = a + (n - 1)d

➡ 180 = 2 + (n - 1)2

➡ 180 = 2 + 2n - 2

➡ n = 180/2

➡ n = 90

The no. of terms is 90.

Now it's sum = n/2 (a + l)

= 90/2 (2 + 180)

= 45 × 182

= 8190

Hence, The average of the numbers = (sum of all numbers)/(total no.s)

= 8190/90

= 91 final answer!

Answer 2

Answer:

For showing Full answer click on photo.