The average velocity of a body moving at a constant acceleration at regular intervals t1,t2,t3 is V1,V2, V3
, respectively, which is the correct correlation
a) (v₁ − v₂): (v₂ − V3) = (t₁ −1₂): (t₂ +t3)
(ஆ) (v1-v2) : (v2-v3) = (t1+t2) : (t2+ t3)
(இ) (v1-v2 ) : (v2-v3)=(t1-t2) :(t1-t3)
(ஈ) (v1 - v2) : (v2-v3) =(t1-t2) : (t2-t3)
Answers
Answered by
2
Answer:
(B)Let u be the initial velocity
∴v
1
=u+at
1
,v
2
=u+a(t
1
+t
2
)
and v
3
=u+a(t
1
+t
2
+t
3
)
Now v
1
=
2
u+v
1
=
2
u+(u+at
1
)
=u+
2
1
at
1
v
2
=
2
v
1
+v
2
=u+at
1
+
2
1
at
2
v
3
=
2
v
2
+v
3
=u+at
1
+at
2
+
2
1
at
3
So (v
1
−v
2
)=−
2
1
a(t
1
+t
2
)
and (v
2
−v
3
)=−
2
1
a(t
2
+t
3
)
∴(v
1
−v
2
):(v
2
−v
3
)=(t
1
+t
2
):(t
2
+t
3
)
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