Question

the average velocity of a body moving with uniform acceleration after travelling a distance of 3.06m in 0.34m/s. if the change in velocity of the body is 0.18m/s during this time , uniform acceleration is A. 0.01m/s B. 0.02m/s C. 0.03m/s D. 0.04m/s

Answer 1

hope it helps u.......

Answer 2

Answer:

Concept:

The acceleration of the particle is the frequency at which velocity changes.

The rate at which velocity changes in relation to time is known as acceleration. Since acceleration is a vector quantity, its direction will coincide with the direction of the velocity's rate of change.

As the name implies, uniformly accelerated motion refers to a body or object moving at a consistent rate of acceleration. The absence of velocity does not imply constant acceleration. Therefore, if a body is in motion such that the amount of change in its velocity over equal time intervals will be constant, it is said to be experiencing uniform acceleration.

Explanation:

Given:

A body is moving with uniform acceleration

Distance = 3.06 m

Average velocity = 0.34m/s

Change in velocity of the body = 0.18m/s

Find:

Uniform acceleration when change in velocity of the body

Solution:

                     $\mathrm{V}_{\mathrm{avg}}=\frac{\mathrm{D}}{\mathrm{t}} \Rightarrow 0.34=\frac{3.06}{\mathrm{t}}$

                               $\Rightarrow \mathrm{t}=\frac{3.06}{0.34}=9 \mathrm \ {sec}$

                       we have,    $\mathrm{v}=\mathrm{u}+ at$

                                             $\begin{aligned}&\mathrm{v}-\mathrm{u}=\mathrm{at} \\&0.18=\mathrm{a} \times 9 \\&\Rightarrow \mathrm{a}=\frac{0.18}{9}=0.02 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}$

The average velocity of a body moving with uniform acceleration after traveling a distance of 3.06m in 0.34m/s. if the change in velocity of the body is 0.18m/s during this time, uniform acceleration is $0.02 \mathrm{~m} / \mathrm{s}^{2}$

                              Hence option (B) is correct.

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