Physics, asked by nkashyap1033, 8 months ago

The average velocity of a car that is driven 15km east for 22minutes before the road changes.The car is then driven 18km south for 18mins

Answers

Answered by abhijitsingha79
0

Answer:

Since it's travelling in the same direction for the entire duration of its journey, the total displacement of the car is simply the distance from the starting point.

In the first part of its journey, the car travelled for 35 minutes at a speed of 85 km/h. Convert the time from minutes to hours to get

35

min

1 h

60

min

=

0.5833 h

This means that the car covered

0.5833

h

85 km

1

h

=

49.6 km

The car stops, then continues along its current direction, covering 130 km in 2 hours. The total displacement of the car will thus be

d

total

=

49.6

+

130

=

179.6 km

The average velocity is simply the total dispalcement divided by the total time of travel. In your case, the total time will be

t

total

=

0.5833 h

+

0.25 h



= 15 min

+

2 h

=

2.833 h

The average velocity is

¯

v

=

179.6 km

2.833 h

=

63.4 km/h

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