Physics, asked by asachdev03, 6 months ago

The average velocity of a freely falling body is numerically equal to half of the accelaration due to gravity. What is the velocity of the body as it reaches the ground? Pls write the steps as well

Answers

Answered by Anonymous
1

Explanation:

Since it is a free fall, average velocity, v=tS=t21gt2=2g, where t is the time of descent and initial velocity is zero. We know that for a free fall, velocity with which it reaches the ground: V=gt, where t is time of descent .

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