Question

The average velocity of the vehicle is 180 km/hr. It requires 2000 W for operation of30 min. Find the magnitude of constant tractive effort.​

Answer 1

Answer:

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Answer 2

The magnitude of constant tractive effort is 40 N.

Explanation:

Given that,

The average velocity of the vehicle, v = 180 km/hr = 50 m/s

Power of the vehicle, P = 2000 W

Time, t = 30 min

We need to find the magnitude of constant tractive effort.​ Tractive effort is equal to the force. The power of an object in terms of force and velocity is given by :

$P=F\times v$

F is Tractive effort

$F=\dfrac{P}{v}\\\\F=\dfrac{2000\ W}{50\ m/s}\\\\F=40\ N$

So, the magnitude of constant tractive effort is 40 N.

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