Question

The average weekly expenditure on a particular commodity incurred by families in a certain locality is normally distributed with a mean of Rs.125 and a standard deviation equal to Rs.25. What is the probability that a family selected at random from the locality, will have an average weekly expenditure on the given commodity in excess of Rs.175 ? What is the probability that out of eight families selected from the locality, at least one family will incur an average weekly expenditure on the given commodity in excess of Rs.175 ?

Answer 1

Answer:

The average weekly expenditure on a particular commodity by families in a certain locality is normally distributed 125+125= 150 probability.

175+175= 350 locality.