the average weight of 10 oarsman in a boat is increased by 1.8 kg when one of the crew ,who weighs 53 kg is replaced by a new man .find the weight of the new man
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Let the total weight of the 9 men who do not get replaced be "n" and the weight of the new man be "x".
According to question:
{(n+53) / 10} + 1.8 = (n+x) / 10 (applying formula for calculating average )
=> (n + 53 + 18) / 10 = (n+x) / 10 (talking lcm of LHS)
=> n+71=(n+x) (multiplying 10 both sides)
=> x = 71 (cancelling n from both sides)
THEREFORE the weight of the new man is 71 Kg..
According to question:
{(n+53) / 10} + 1.8 = (n+x) / 10 (applying formula for calculating average )
=> (n + 53 + 18) / 10 = (n+x) / 10 (talking lcm of LHS)
=> n+71=(n+x) (multiplying 10 both sides)
=> x = 71 (cancelling n from both sides)
THEREFORE the weight of the new man is 71 Kg..
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