Question

The average weight of 11 students is 50 kg. These students are made to stand in a row. The averageweight of the first six students is 49 kg and the average weight of the last síx students is 52 kg. Now,the teacher asked the sixth student to leave the place. What is average weight of the remainingstudents​

Answer 1

Answer:

50.5

Step-by-step explanation:

as the common 6th student moves the average will be 49+52/2=50.5

Answer 2

Concept

In Maths, a median of a listing of information is that the expression of the central value of a collection of information. The formula to calculate the typical of given numbers is adequate the sum of all the values divided by the whole number of values.

Given

We are given the common weight of $11$ students is $50kg$ the common weight of the primary six students is $49kg$ and also the average weight of last six students is $52kg.$

Find

We have to search out the typical weight of the remaining students.

Solution

Firstly, we are going to find the sum of the weights by using the common formula.

$\text{Average}&=\frac{\text{Sum of weights }}{\text{total sudents}}$.       .......(1)

The average weight of scholars is $50kg$ and therefore the sum of weights is $S_{1}$ and therefore the total students is $11.$

Substitute these values within the above formula, we get

$\begin{aligned}50&=\frac{S_{1}}{11}\\ 550kg&=S_{1}\end$

Now, we'll find the sum of weight of first six students, we get

The average weight of first six students is $49kg$ and also the sum of weights is $S_{2}$.

Substitute these values within the equation (1), we get

$\begin{aligned}49&=\frac{S_{2}}{6}\\ 294kg&=S_{2}\end$

Further, we'll find the sum of weight of last six students, we get

The average weight of last six students is $52kg$ and also the sum of weights is $S_{3}$.

Substitute these values within the equation (1), we get

$\begin{aligned}52&=\frac{S_{3}}{6}\\ 312kg&=S_{3}\end$

Furthermore, we'll find the whole weight of scholars by adding sum of weight of first six students and sum of last six students.

$\begin{aligned}S&=S_{2}+S_{3}\\ &=294+312\\ &=606kg\end$

Now, we are going to find the weight of sixth student, we get

$\begin{aligned}S_{4}&=606-550\\ &=56kg\end$

Further, we are going to the common weight of the remaining students by substituting the values in equation (1), we get

$\begin{aligned}\text{average}&=\frac{550-56}{10}\\ &=\frac{494}{10}\\ &=49.4kg\end$

Hence, the common weight of remaining student is $49.4kg.$

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