Question

The average weight of first 9 persons among 10 persons is 50 kg. The weight of 10th person is 18 kg more
than the average weight of all the 10 persons. The weight of the 10th person is
A
65 kg
B
28 kg
C
70 kg
D) 75 kg​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Concept:

The average is defined because the average which is capable the ratio of the sum of the quantity of a given set of values to the whole number of values present within the set.

Given:

we are given the typical weight of first $9$person among $10$ person is $50kg$ and also the weight of $10th$ person is $18$kg quite the typical weight of all the$10$ person.

Find:

we have to search out the load of $10th$person.

Solution:

Let the common weight of $10$ person is $=x$

and weight of $10$ persons is $x+18$

According to the question,

$\begin{aligned}\frac{9\times 50+x+18}{10}&=x\\ \frac{450+x+18}{10}&=x\\ 450+x+18&=10x\end$

Now, we are going to find the worth of $x,$ we get

$\begin{aligned}468&=9x\\ \frac{468}{9}&=x\\ 52&=x\end$

Hence, The load of $10$th person is $52+18=70kg$ and also the option is C correct.

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