Math, asked by gauravv25, 9 months ago

The average weight of three men A B and C is 84 kg and other man D joins the group and the average now becomes 80 Kg if another man E whose weight is 3 kg more than that of B replaces A, then average weight of B, C, D and E becomes 79 kg, the weight of A is ?​

Answers

Answered by js45756825373
7

Step-by-step explanation:

Total weight of A + B + C = 84 x 3 = 252 kg

Total weight of A + B + C + D = 80 x 4 = 320 kg

∴ Weight of D = 320 - 252 = 68 kg

Given, E = D + 3 = (68 + 3) kg = 71 kg

Total weight of B + C + D + E = (79 x 4) kg = 316 kg

∴ Weight of B + C = 316 kg - 71 kg - 68 kg = 177 kg

Weight of A only = 320 kg - 177 kg - 68 kg = 75 kg

Answered by srinumocharla
1

Step-by-step explanation:

a+b+c/3 =84

a+b+c = 84 *3 = 252

a+b+c+d/4 = 80

a+b+c+d = 320

b+c+d+(b+3) /4 = 79

b+c+d+b+3 = 316

We know that

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