Question

the averege value of
$y = 3x { }^{2} + 3$
In the interval
$0 \leqslant x \leqslant 2$
​

Answer 1

Y= 3x²+3

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Answer 2

Answer:

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Explanation:

x=0,1,2

y=3×0^2+3=0+3=3

y=3×1^2+3=3+3=6

y=3×2^2+3=3×4+3=12+3=

15