The averge of the 3 no is 77. The frst no is twice the second and the second is twice the third find the first no
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let the first no be x , second no = 2x
third no = 4x
BTQ ,
(x+ 3x+4x)/3= 77
7x/3= 77
x/3= 11
x= 33
The first no is 33
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third no = 4x
BTQ ,
(x+ 3x+4x)/3= 77
7x/3= 77
x/3= 11
x= 33
The first no is 33
PLEASE MARK AS BRAINLIEST
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