Question

the avg force that is necessary to step with a momentum of 20 Ns in 0.2 sec is about

please say answer​

Answer 1

Explanation:

f =(mv-mu) ÷ t

f= 0-20) ÷ 0.2

f= -100N

the negative sign indicates the force acts in opposite direction

F= 100N

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

Find the average force that is necessary to step with a momentum of $20 Ns$ in $0.2 sec.$

$\huge\bold{\mathtt{Solution⇒}}$

The initial momentum is $mu = 20 Ns$

The final momentum is $mv = 0 Ns$

Time $= 0.2 s$

According to Newton's second law of motion,

$F = {\frac{mv-mu}{t}}$

$➳\:F = {\frac{0-20}{0.2}}$

$➳\:F = {\frac{(-20)}{0.2}}$

$➳\:F = -100$

The negative sign indicates that the force is acting in opposite direction.

The average force that is necessary is $100N.$

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