Question

The AWG (American Wire Gauge) is used as a standard method denoting wire diameter,

measuring the diameter of the conductor (the bare wire) with the insulation removed. An

AWG # 12 copper wire (a size in common use in residential wiring) contains approximately

2.77 x 1023 free electrons per meter length, assuming one free conduction electron per atom.

What percentage of these electrons will pass a fixed cross section in one second if the conductor

carries a constant current of 1.5 A?​

Answer 1

Answer:

ffahiofsifsiffgyhyyyyy

Answer 2

0.202 % of these electrons will pass a fixed cross-section in one second.

Given:

Free electrons per meter length = $2.77*10^{23}$

Current = 1.5 A.

To Find:

Percentage of electrons passing through a fixed cross-section in one second.

Solution:

Electrons passing the cross-section in one second:

Current÷Electrons in 1 A current

i.e.  $1.5/1.602*10^{-19}$

     $= 9.36*10^{18}$ electrons/second

Electrons passing the cross-section in one minute:

i.e.  $9.36*10^{18}*60$

     $= 5.616*10^{20}$ electrons/minute

To get the percentage of these electrons passing through a cross-section we have to divide the finding by free electrons per meter length and then multiply by 100:

i.e.

  $5.616*10^{20} /2.77*10^{23}*100$

$= 0.202%$ %

Hence, 0.202% of these electrons will pass a fixed cross-section in one second.