Physics, asked by udhyotgandhi3, 11 months ago


The axis of a polariser and an analyser are parallel to each other. Then the emitted intensity Io is obtained. If the a
is rotated by 45° then find the value of the emitted intensity.

Answers

Answered by aristocles
2

Answer:

the intensity of the light becomes half when we turn it by 45 degree

Explanation:

As we know that when polarizer and analizer is parallel to each other then the intensity of light is maximum

So here we know that by Malus law we have

I = I_o cos^2\phi

now when we rotate the analyser by 45 degree angle then we have

I = I_o cos^245

I = \frac{I_o}{2}

so the intensity of the light becomes half when we turn it by 45 degree

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Topic : Polarization

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