Question

The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?

Answer 1

Answer:

f(x) = x^2 + bx + 10 =0

= (6)^2 + b.6 + 10 =0

= 36 + 6b + 10 =0

=36 + 6b = -10 =0

= 6b = -10 - 36 =0

= b = -46/6

= b = -7.666

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Answer 2

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Value of b = -3 if The axis of symmetry for the graph of the function f(x) = x²/4  + bx  + 10  is 6

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f(x) = x²/4  + bx  + 10

The axis of symmetry for the graph of the function is 6

so root would be

6 + a  & 6 - a

Sum of Roots = 6  + a + 6 - a = 12

Sum of roots  = - b/a  =   -b/(1/4)  = - 4b

-4b = 12

=> b = -3

Value of b = -3

Value of b = -3 if The axis of symmetry for the graph of the function f(x) = x²/4  + bx  + 10  is 6