Question

The azimuthal quantum number for the last electron of sodium is

Answer 1

Answer:

l = 0

Explanation:

Na

Electronic configuration of Na ;

$\green\displaystyle{1s^2 \ 2s^2 \ 2p^6 \ 3s^1}$

Principal quantum number ;

n = 3

Azimuthal quantum number ;

We know ,

l vary 0 to n - 1 for all l

l = 0 to 3 - 1

l = 0 to 2

l = 0 , 1 , 2

We know for

s  ⇒  l   =  0

p  ⇒  l  =   1

d  ⇒  l  =   2

f   ⇒  l  =   3

In Na last one is 4 s¹

So , particular value of l for Na is 0 .

Thus we get answer .

Answer 2

Answer:

ur answer is 0

i hope it will help u

Explanation: