Question

The bacteria in a culture grows b 10% in the first 10 hour, decreases by 10% in the second hour and again increases by 10% in the next hour. If the original count of the bacteria in a sample is 10,000, find the bacteria count at the end of the 3 hours

Answer 1

It is stated that,

The number of bacteria present in a sample is 10,000

It increases by 10% in the first hour then decreases by 10% in the second hour, then again increases by 10% in the third hour.

Since, it is increasing compoundly in number.

So, the bacteria count after 3 hours_

$10000×(1+10/100)×(1-10/100)×(1+10/100)\\= 10000×(1+1/10)×(1-1/10)×(1+1/10)\\= 10000×{(10+1)/10}×{(10-1)/10}×{(10+1)/10}\\= 10000×(11/10)×(9/10)×(11/10)\\= 10×11×9×11\\= 121×90\\= 10890$

So, the bacteria count after 3 hours is 10890.

Answer 2

Step-by-step explanation:

check the attachment (◍•ᴗ•◍)❤