The bacteria in a culture grows by 10% in first hour, decreases by 10% in second hour. If the original number of bacteria are 10,000. Find the no. of bacteria after 2 hours.
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Step-by-step explanation:
The number of the bactera at the onset=10000.
We know that Finalcount=initialcount±((initialcount)×
100
time×rate
).
∴ In the first hour, the number increases by 10%,so total number of count becomes
10000+(10000×
100
10
)=11000.
In the second hour, the number decreases by 10%
So the rate is negative.
∴ In the second hour, the number of bacteria is
11000−(11000×
100
10
)=9900.
In the third hour the number of bacteria increases by 10%
∴ In the third hour, the number of bacteria is
9900+(9900×
100
10
)=10890.
So, at the end of 3hours the number of bacteria is 10890.
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