Question

The bacteria in a culture grows by loose in the
first hour, decreases by 10% in the second hour and
again. Increases by loose in the third hour. If the
original count of the bacteria in a sample is toooo
find the bacteria count at the end of 3 hours.
Gulate​

Answer 1

The number of the bactera at the onset=10000.

We know that Finalcount=initialcount±((initialcount)× 100/time×rate ).

∴ In the first hour, the number increases by 10%,so total number of count becomes

10000+(10000× 100/10 )=11000.

In the second hour, the number decreases by 10%

So the rate is negative.

∴ In the second hour, the number of bacteria is

11000−(11000× 100/10 )=9900.

In the third hour the number of bacteria increases by 10%

∴ In the third hour, the number of bacteria is

9900+(9900× 100/10)=10890.

So, at the end of 3hours the number of bacteria is 10890.

its the answer....