Question

The balanced equation for a reaction is given below
2x + 3y → 4l + m
When 8 moles of x react with 15 moles of y, then
i) Which is the limiting reagent?
ii) Calculate the amount of products formed.
iii) Calculate the amount of excess reactant left at the end of the reaction.

Answer 1

From the equation 2x + 3y → 4l + m

2 moles of x react with 3 moles of y

∴ 8 moles of x is supposed to react with 3/2 x 8 moles of y = 12 moles

Since we have 15 moles of y, it means y is in excess


i) The limiting reagent is x

2 moles of x produce 4 moles of l and 1 mole of m

ii) 8 moles of x will produce 2x8 = 16 moles of l
   
    8 moles of x will produce 1/2 x 8 moles of I = 4 moles


iii) Excess reactant is y

Excess y = 15 moles - 12 moles =  3 moles