Question

the balanced equation shown below if the reaction 20.7 grams of caco3 produces 6.81 grams of CA what is the percent yield caco3 gives rise to ca + CO2​

Answer 1

$\sf {CaCO_{3} ---> CaO + CO_{2}}\\\\\\\sf {20.7\ g\ 6.81g\ +}$

As per the law of Conservation of mass, in any chemical reaction, the total mass of products is equal to the total mass of the reactants.

Mass of C O₂  + Mass of CaO = Mass of CaC O 3  

Mass of C O ₂  + 6.81g = 20.7g

Mass of C O  ₂ = 20.7g- 6.81g = 13.89g

$\sf {\%\ yield\ of\ a\ Product\ Z\ = Mass\ of\ product\ Z \times \frac{100}{Mass\ of\ Reactant}}\\\\\\\sf {\%\ yield\ of\ Product\ CO_{2} = 13.89 \times\frac{100}{20.7} = 67. 10%}$

$\sf {\%\ yield\ of\ Product\ CaO = 6.81g \times \frac{100}{20.7} = 32.89%}$