Question

The balanced net ionic equation for the reaction of aluminium sulphate and sodium hydroxide

Answer 1

Answer:

$Al^3^+ + 3OH^- = Al(OH)_3$

Explanation:

The unbalanced molecular equation is:

$Al_{2}(SO_{4})_{3} + NaOH = Al(OH)_{3} + Na_2SO_4$

$Al(OH)_3$ is a precipitate, but the rest of the compounds are in aqueous form and split into ions.

The unbalanced complete ionic equation is

$Al^3^+ + SO_4^2^- + Na^+ + OH^- = Al(OH)_3 + Na^+ + SO_4^2^-$

The balanced net ionic equation is

$Al^3^+ +3OH^- = Al(OH)_3$