Question

The balanced reaction is : CaCO3 + 2 HCl CaCl2 + CO2 + H2O

You collect the following data:
Mass of evaporating dish: 49.045 g
Mass of evaporating dish with CaCO3: 49.602 g
Mass of evaporating dish with dried CaCl2: 52.130 g

a) Using the data, calculate the experimental mole ratio of CaCO3: CaCl2. Show and label your work, show units, sig figs, etc

b) Based on your calculations above, in your expert opinion, do you think the data reflects a decent experiment or should it be repeated? Explain.

Answer 1

Answer:

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Explanation:

CaCO3 + 2HCl -----> CaCl2 + H2O + CO2.

2.5g? g

Mass of CaCO3= 40+12+3(16)=52+ 48= 100.

Molar mass of CaCO3=100g.

Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111.

Molar mass of CaCl2=111g.

Mass of CaCO3 (g) Mass of CaCl2 (g)

For 100g of CaCO

3

, 111g of CaCl_2$$ is formed.

let for 2.5g of CaCO

3

, x g of CaCl

2

is formed.

Thus, by cross multiplication,

x=111×2.5/100=2.775g=2.78g.