Question

the ball is dropped from a height of 20m on a floor ifit is found that the ball rises up to 5 metre after second bounds then coefficient of resultant for the coefficient between the ball and the floor is​

Answer 1

Explanation:

Initially it reaches ground with a velocity of

2gh

=20m/s

Let the velocity of separation after first collision be x

And the velocity of collision after second collision be y,

Then as per equation of e,

20

x

=

2

1

and

x

y

=

2

1

Solving we get y=5m/s

So height attained by ball after second collision =

2g

y

2

=1.25m

Answer 2

Answer:

20 m+5 m=25m

Explanation: