The ball is dropped from top of a tower of 100 m height. simultaneously another ball was thrown upward from the bottom of the tower with speed of 50 m/s. they will cross each other after
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Question
The ball is dropped from top of a tower of 100 m height. simultaneously another ball was thrown upward from the bottom of the tower with speed of 50 m/s. they will cross each other after
Solution
Suppose they will cross each other after time t then the sum of the value of their displacement should be equal to height of tower.
Now displacement of first ball in time t is gt²/2
and for second ball it will be ut − gt²/2
adding them we will get ut which should be equal to 100meter
so t = 2second.
Therefore 2 seconds is your answer
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