Question

The ball is projected vertically upwards.
from a ground with an initial velocity
of 9.8ms Find the manimum
reached by it using the lace of conservat
on of Energy​

Answer 1

Answer:

4.9m

Explanation:

see the attached explanation

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Answer 2

$\sf \fcolorbox{red}{pink}{ \huge{Solution :)}}$

Given ,

• The velocity of ball which is vertically projected is 9.8 m/s

We know that , the Newton's third equation of motion is given by

$\large \sf \fbox{ {v}^{2} - {u}^{2} = 2as}$

According to the question ,

$\sf \large \fbox{ {v}^{2} - {u}^{2} = - 2gh }$

Here ,

v = 0

u = 9.8 m/s

g = 9.8 m/s

Substitute the known values , we get

$\sf \hookrightarrow {(0)}^{2} - {(9.8)}^{2} = - 2 \times 9.8 \times h \\ \\\sf \hookrightarrow 9.8 = 2h \\ \\ \sf \hookrightarrow h = \frac{98}{20} \\ \\\sf \hookrightarrow h = 4.9 \: \: m$

Hence , the manimum height reached by ball is 4.9 m

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