Question

The Ball Is Thrown Vertically Upwards With Velocity Of 49 M/S . Calculate The Maximum Height. .. 2. Find Total Time It Return To The Surface

Answer 1

Answer:

g=9.8 m/s²

H(max)= u²/2g

= (49 x 49)/19.6

= 122.5m

T= 2u/g

=98/9.8

=10 s

Answer 2

Answer:

Hi friend

--------------

Your answer

---------------------

here,

Final velocity = V = 0 m/s ,

Initial velocity = u = 49 m/s ,

Acceleration due to gravity = a = g = - 9.8 m/s² ,

Height = s = ?

So,

------

v² - u² = 2as

=> v² - u² = 2×g×s

=> (0)² - (49)² = 2 × (- 9.8) × s

=> - (49 × 49) = - ( 2 × 9.8 × s)

=> s = (49 × 49) / (2 × 9.8)

=> s = 122.5 m

HOPE IT HELPS