Question

The balloon filled with acetylene is kept in a vessel of hydrogen at same temperature and pressure. If the balloon is punctured with the pin it bursts why??

Answer 1

${\huge{\underline{\small{\bold{\red{Answer}}}}}}$The balloon filled with acetylene is kept in a vessel of hydrogen at same temperature and pressure. If the balloon is punctured with the pin it bursts because the hydrogen pressure comes out ...

Graham's law of diffusion ....

Answer 2

Answer:

If the balloon is punctured with a pin, then it bursts because of the more effusion of hydrogen gas ( Graham’s law of effusion ).

Explanation:

Graham’s law of effusion:

It states that under similar conditions of constant temperature and pressure, the ratio of the rates of diffusion or effusion of gases are inversely proportional to the ratio of square root of their molar masses or densities.

$\frac{Rate 1}{Rate 2} = \frac{\sqrt{M1} }{\sqrt{M2} }$ ,  

Here,

Rate1 = rate of effusion of the gas 1

Rate2 = rate of effusion of the gas 2

M1 = molar mass of gas 1

M2 = molar mass of gas 2

Molar mass of acetylene:

• C₂H₂ = 2 × atomic mass of carbon + 2 × atomic mass of hydrogen

        = 2 × 12 + 2 × 1

        24 + 2 = 26 g/mol

Molar mass of hydrogen gas:

• H₂ = 2 × atomic mass of hydrogen

             = 2 × 1 = 2 g/mol

As we can see, the molar mass of hydrogen is much lower than that of acetylene.

So, according to Graham’s law of effusion, rate of effusion of hydrogen gas will be much greater than the acetylene.

Therefore, hydrogen gas will effuse more into the balloon when it is punctured with a pin.

Hence it will enlarge the balloon and result in bursting of the balloon.

RESULT: Because hydrogen gas will effuse more into the balloon when it is punctured with a pin results in the bursting of the balloon.