The bandwidth required for the transmission of a pcm signal increases by a factor of -------- when the number of quantization levels is increased from 4 to 64.
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(bandwidth )pcm = nfm
Where n – number of bits in PCM code
fm – signal bandwidth
n=log2L
n1 =log 2^4=2
n2=log2 64= 6
(BW) 1=n1fm=2fm
(BW) 2=n2fm=6fm
(bw) 2/(bw) 1 = 6fm/2fm
= 3times
(bw)2 = 3(bw) 1
So, increase is 3 times
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(bandwidth )pcm = nfm
Where n – number of bits in PCM code
fm – signal bandwidth
n=log2L
n1 =log 2^4=2
n2=log2 64= 6
(BW) 1=n1fm=2fm
(BW) 2=n2fm=6fm
(bw) 2/(bw) 1 = 6fm/2fm
= 3times
(bw)2 = 3(bw) 1
So, increase is 3 times
if u like my answer then mark brainy answer
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