The banking angle of a curved road is
tan^-1 (3/5) and its radius of curvature
is 5m, then the safe driving speed of v
vehicle travelling on the road, is
( g=10m/s^2 )
Options
1) √10 ms^-2
2) √20 ms^-2
3) √30 ms^-2
4) √40 ms^-2
Answers
Answered by
1
Answer:
√30 m/s
Explanation :
Safe driving speed is given by
V =√ rg tanα
where r is the radius of curvature
α is the angle of banking of the road
that is
V = √ 5 * 10 * 3/5
= √30 m/s
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