Question

the bas of isosceles triangle is 12cm and its perimeter is 32cm. find its area

Answer 1

let the equal sides be x, now x+x+12cm = 32cm
2x=20cm
x=10cm

semi perimeter (s)= ½perimeter
s= 16cm

area of triangle:
$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{16 \times 4 \times 6 \times 6} \\ = 4 \times 2 \times 6 \\ = 48cm { }^{2}$