Question

the base AB of two equilateral triangles ABC and ABC- with side 2a lies along the x axis such that the mid point of AB is at the origin .find the coordinates of the vertices C and C- of the triangles

Answer 1

so the vertices of C will be (0.a√3)
and another C will be (0, - a√3)

Answer 2

using Pythagoras theorem we get length of c on y axis = √(4a² - a²)
is '+' tive '-' tive direction of x axis
  so the vertices of C will be (0.a√3)
and another C will be (0, - a√3)