Question

The base and altitude of a 11 gm are respectively 12cm and 18 cm the area of parallelogram is equal to the area of atriangle whose base is 54 cm. Find the height of the triangle.

Answer 1

this is the answer for your question

Answer 2

area of parallellogram =base×height
=12 x 18
=216
area of ∆=1/2 ×bxh
=0.5×54×h
216=27h
h = 8 cm ✓