the base and altitude of a triangle are (3x-4y) and (6x+5y) respectively. find its area.
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We can approach this question by simply applying the area of a triangle formula
Which is:
Half of base times corresponding height
1/2*base*corresponding height
So since we don’t have an exact constant value we’ll have to simplify by using the variables.
Hence, on substituting
Base=(3x-4y) Corresponding altitude=(6x+5y)
We get
Area= 1/2*(3x-4y)*(6x+5y)
=> 1/2*[3x(6x+5y)-4y(6x+5y]
=> 1/2*[18x^2+15xy-24xy-20y^2]
=> 1/2*[18x^2-9xy-20y^2]
Hence the area will be 1/2*[18x^2-9xy-20y^2]
Thanks:)
Which is:
Half of base times corresponding height
1/2*base*corresponding height
So since we don’t have an exact constant value we’ll have to simplify by using the variables.
Hence, on substituting
Base=(3x-4y) Corresponding altitude=(6x+5y)
We get
Area= 1/2*(3x-4y)*(6x+5y)
=> 1/2*[3x(6x+5y)-4y(6x+5y]
=> 1/2*[18x^2+15xy-24xy-20y^2]
=> 1/2*[18x^2-9xy-20y^2]
Hence the area will be 1/2*[18x^2-9xy-20y^2]
Thanks:)
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