Question

The base and altitutde of a trangal are in the ratio 3:4and its aea is 96cm. find its base and altitude

Answer 1

Since the base and height of a triangle are in the ratio 3:4.
So suppose the base and height of triangle are 3x and 4x respectively.

Answer 2

Answer:

The base of the triangle is 12 cm and altitude is 16 cm.

Step-by-step explanation:

The base and altitude of a triangle are in the ratio 3:4

Let the ratio be x

So, base = 3 x

Altitude = 4 x

Area of triangle = $\frac{1}{2} \times Base\times Altitude$

Since we are given that the area of the given triangle is 96 sq. cm.

So, $96=\frac{1}{2} \times 3x \times 4x$

$96= 6x^2$

$16= x^2$

$4 =x$

So base = 3x= 3*4 = 12 cm

Altitude = 4x=4*4=16 cm

Hence the base of the triangle is 12 cm and altitude is 16 cm.