Question

The base and another side of an isosceles triangle is 8 cm and 12 cm. Find its area??
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Answer 1

Answer:

48

Step-by-step explanation:

formula of isosceles

1÷2×base ×height

1÷2× 8 × 12

0.5 × 8 × 12

4 ×12=48 the area of isosceles triangles 48

Answer 2

Answer: The required area is 17.88 sq. cm.

Step-by-step explanation:

Since we have given that

Base side = 8 cm

Another side (which is equal side) = 12 cm

So, Area of isosceles triangle is given by

$\dfrac{b}{2}\sqrt{\dfrac{a^2-b^2}{4}}\\\\=\dfrac{8}{2}\sqrt{\dfrac{12^2-8^2}{4}}\\\\=4\times \sqrt{\dfrac{144-64}{4}}\\\\=4\times \sqrt{\dfrac{80}{4}}\\\\=4\times \sqrt{20}\\\\=17.88\ cm^2$

Hence, the required area is 17.88 sq. cm.