the base and height of a triangle are in ratio 3:4 and its area is 96 cm sq. . find its base and height.
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let the base and height of the triangle are 3x and 4x respectively. then
A.T.Q.
1/2×b×h = 96 cm sq.
(3x)×(4x) = 96×2
12(x)^2 = 96×2
( x )^2 = 16
x. = √16
x = 4cm
and hence, base = 3×4 = 12cm and height = 4×4 = 16 cm.
A.T.Q.
1/2×b×h = 96 cm sq.
(3x)×(4x) = 96×2
12(x)^2 = 96×2
( x )^2 = 16
x. = √16
x = 4cm
and hence, base = 3×4 = 12cm and height = 4×4 = 16 cm.
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