the base and height of a triangle are in the ratio 3 :3 and its area is 108 sq cm find its base and hight
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area of triangle = 1/2 X base X height.
area = 1/2 X 2x X 3x =
base = 3 X 6 = 18
height = 2 X 6 = 12
area = 1/2 X 2x X 3x =
base = 3 X 6 = 18
height = 2 X 6 = 12
Answered by
1
given , ratio of base and height = 3 : 2
let the constant ratio be " x "
now base and height of triangle are , 3x , 2x
given , area = 108 cm^2
1/2 × base × height= 108 cm^2
1/ 2 ×3x × 2x = 108
6x^2 = 108×2
6x^2 = 216
x^2 = 216 /6 = 36
x^2 = 36
x = √36
x = 6
now base = 3x = 3 × 6 = 18 cm
height = 2x = 2×6 = 12 cm
hence, hence and height of triangle are 18 cm and 12cm.
____________________
【your answer : B = 18 cm ,H =12 cm】
____________________
let the constant ratio be " x "
now base and height of triangle are , 3x , 2x
given , area = 108 cm^2
1/2 × base × height= 108 cm^2
1/ 2 ×3x × 2x = 108
6x^2 = 108×2
6x^2 = 216
x^2 = 216 /6 = 36
x^2 = 36
x = √36
x = 6
now base = 3x = 3 × 6 = 18 cm
height = 2x = 2×6 = 12 cm
hence, hence and height of triangle are 18 cm and 12cm.
____________________
【your answer : B = 18 cm ,H =12 cm】
____________________
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