Question

The base and height of a triangle in the ratio 3:2 and its is 108m² .Find its base and height.​

Answer 1

Given:-

$\bf\implies ratio \longrightarrow 3:2$

$\bf\implies Area \longrightarrow 108m²$

To Find:-

$\bf\implies Base and height$

Solution:-

Let x be multiple of ratios.

$\bf\implies 3x+2x \longrightarrow \frac{108}{2}$

$\bf\implies 5x \longrightarrow 54$

$\bf\implies x \longrightarrow \frac {54}{5}$

$\bf\implies x \longrightarrow 10.8$

$\bf\implies 3x\longrightarrow 32.4m×2=64.8m$

$\bf\implies 2x \longrightarrow 21.6m×2=43.2m$

$\bf\implies\boxed{ Base \longrightarrow 64.8m}$

$\bf\implies\boxed {Height \longrightarrow 43.2m}$

Answer 2

Step-by-step explanation:

let the ratio be x

base=3x,height=2x

area of triangle=108cm2

ATQ

1/2×2x×3x=108cm2

3x2=108

x2=36

x=6

base=3×6=18cm

height=2×6=12cm