the base and height of a triangle is 9 and 5 respectively the base of height of another triangle is 10 and 6 respectively find the ratio of the area of the first triangle to the area of the Other Triangle
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Answer:
ratio of area of triangle = base1 ×height1 /base2×height2
=9×5/10×60
=45/60
=3/5
Answered by
0
Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)/A(△PQR)
=AB×BC/PQ×QR
=5×9/6×10
=3/4
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