Question

the base and height of a triangle is 9 and 5 respectively .the base and height of another triangle is 10 and 6 respectively find the ratio of the area of the first triangle to the area of the other triangle​

Answer 1

Answer:

area of first triangle = 1/2 * 9*5 = 22.5

area of Second triangle = 1/2 * 10 *6 = 30

now according to question ratio = 22.5/30 = 225/300 = 15/20 = 3/4 = 3:4

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Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4