Question

the base and height of a triangle is 9 and 5 respectively. the base and height of another triangle is 10 and 6 respectively. find the ratio of the area of the first triangle to the area of the other triangle.

Answer 1

Base of the first triangle= 9cm
Height of the first triangle= 5cm
Area of the first triangle= 1/2 × base × height
= 1/2×9cm×5cm
= 45/2cm= 22.5cm
Base of another triangle= 10cm
Height of the another triangle=6cm
Area of another triangle = 1/2 × base × height
= 1/2 × 10cm×6cm
= 30cm
Ratio of the area of the first triangle to the area of the another triangle i.e 22.5 : 30

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4