Question

The base and height of a triangles is 9 and 5 respectively. The
buse and height of another triangle is 10 and 6 respectively. Find the
ratio of the area of the first triangle to the area of the other triangle
(A) 9:5
(B) 5:3
(C) 3:4
(D)4:3​

Answer 1

$= \frac{9 \times 5}{10 \times 6 } = \frac{45}{60} = \frac{9}{12} = \frac{3}{4}$

c) 3:4 is correct answer