the Base and height of a triangular field are in the ratio of 3 : 4 and it's area is 1014 cm square find it's base and height
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CONCEPT OF AREAS OF TRIANGLES , APPLICATION OF LINEAR EQUATION , SUBSTITUTION METHOD , SQUARE ROOTS METHOD , FOUR FUNDAMENTAL ARITHMETIC OPERATIONS.
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NOTE :- AR (TRIANGLE) = AREA OF TRIANGLE.
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Given :-
- The Base and height of a triangular field are in the ratio of 3 : 4 and it's area is 1014 cm square
To find :-
- Base and height of triangular field
Solution :-
- Base and height of triangular field are in ratio = 3 : 4
- Area of triangular field = 1014cm²
Let the base 3x then height be 4x
Now,
Area of triangular field = ½ × base × height
→ 1014 = ½ × 3x × 4x
→ 1014 = 3x × 2x
→ 1014 = 6x²
→ x² = 1014/6
→ x² = 169
→ x = √169
→ x = ± 13cm
- Base and height never in negative
→ x = 13 cm
Hence,
- Base of triangular field = 3x = 39cm
- Height of triangle field = 4x = 52cm
More to know :-
- Area of circle = πr²
- Circumference of circle = 2πr
- Perimeter of rectangle =2(l + b)
- Perimeter of square = 4 × side
- Area of square = side × side
- Area of rhombus = ½ × product of diagonals
- Area of Parallelogram = base × height
- Area of trapezium = ½ × sum of parallel sides × height
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