Question

The base and height of ∆LMN are 8cm and 6cm respectively. the base and height of ∆DEF are 10cm and 4 cm respectively. write the ratio A(∆LMN):A(∆DEF).​

Answer 1

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Answer 2

The ratio of A(triangle LMN):A(triangle DEF)=6:5

Step-by-step explanation:

Base of triangle LMN=8 cm

Height of triangle=6 cm

Area of triangle =$\frac{1}{2}\times b\times h$

Where b=Base of triangle

h=Height of triangle

Substitute the values then we get

Area of triangle LMN=$\frac{1}{2}\times 8\times 6=24 cm^2$

Base of triangle DEF=10 cm

Height of triangle DEF=4 cm

Using the formula

Area of triangle DEF=$\frac{1}{2}\times 10\times 4=20 cm^2$

Area of triangle LMN:Area of traingle DEF=24:20=6:5

Hence, A(triangle LMN):A(triangle DEF)=6:5

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