Question

the base and height of the∆ are in the ratio 3:2 and it's area is108cm square. Find its base and height​

Answer 1

SOLUTION :

Area of right triangle = $\mathsf{\frac{1} {2}}$ * Base * Height

Here, Given,

Ratio of Base to the height = 3 : 2

Let the base be 3x and height be 2x.

Now,

Area of the triangle = 108$\mathsf{cm}^{2}$

$\mathsf{\frac{1} {2}}$ * Base * Height = 108$\mathsf{cm}^{2}$

$\mathsf{\frac{1} {2}}$ * 3x * 2x = 108

x = $\mathsf{\frac{108}{3}}$

➡️ x = 36 cm.

Now, Base of the triangle = 3x

Base of the triangle = 3* 36 = 108 cm.

Height of the triangle = 2x = 2*36 = 72 cm.

Answer 2

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