the base and height of the triangle are in the ratio of 3:2and it's area is 108cm2 find the base and height
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Answered by
3
Let the base and height be 3x and 2x respectively.
1/2(3x)(2x) = 108
3x² = 108
X² = 36
X = 6
Base = 3(6) = 18 cm
And height = 2(6) = 12 cm
1/2(3x)(2x) = 108
3x² = 108
X² = 36
X = 6
Base = 3(6) = 18 cm
And height = 2(6) = 12 cm
Answered by
3
We are given , base:height = 3:2
Let base = 3k and and height = 2k
We are given, 1/2*base*height = 108
= 1/2*(3k)*(2k) = 108
so, 3k² = 108
k² = 36
So, k =6
hence, base = 3k = 3*6 = 18 cm
and, height = 2k = 2*6 = 12 cm
Let base = 3k and and height = 2k
We are given, 1/2*base*height = 108
= 1/2*(3k)*(2k) = 108
so, 3k² = 108
k² = 36
So, k =6
hence, base = 3k = 3*6 = 18 cm
and, height = 2k = 2*6 = 12 cm
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