Question

the base and hypotenuse of a right angled triangle are respectively 5cm, and 13cm long. find its area. By herons formula

Answer 1

By phythagoras theorem
5^2 + x^2 =13^2
on solving , remaining side =12cm
applying Heron's formula.
area = √{s(s-a)(s-b)(s-c)}
s=(5+12+13)/2=15
so area=√15*10*3*2
=√3*5*5*2*3*2
=√3*3*5*5*2*2
=3*5*2
=30cm^2

Answer 2

Answer:

Step-by-step explanation:

Given base= 5cm

Hypotenuse = 13cm

According  to Pythagoras theorem

$AB^{2} +BC^{2} = AC^{2}$

$AB^{2} + 5^{2} =13^{2}$

$AB^{2} = 13^{2} - 5^{2}$

$AB^{2} =169 -25$

• Area of triangle =   \frac{1}{2}  × base× height $.$

= \frac{1}{2} ×5×12

= 30$cm^{2}$

Project Code = #SPJ3